Base | Representation |
---|---|
bin | 10100101100110011… |
… | …11111101001101111 |
3 | 1001200111200201120101 |
4 | 22112121333221233 |
5 | 140230003100221 |
6 | 5034433131531 |
7 | 542253520555 |
oct | 122631775157 |
9 | 31614621511 |
10 | 11113331311 |
11 | 4793205335 |
12 | 21a19b9ba7 |
13 | 10815580b4 |
14 | 775d71bd5 |
15 | 4509c8d91 |
hex | 29667fa6f |
11113331311 has 2 divisors, whose sum is σ = 11113331312. Its totient is φ = 11113331310.
The previous prime is 11113331269. The next prime is 11113331323. The reversal of 11113331311 is 11313331111.
It is a strong prime.
It is an emirp because it is prime and its reverse (11313331111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11113331311 - 27 = 11113331183 is a prime.
It is a super-2 number, since 2×111133313112 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11113331351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556665655 + 5556665656.
It is an arithmetic number, because the mean of its divisors is an integer number (5556665656).
Almost surely, 211113331311 is an apocalyptic number.
11113331311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113331311 is an equidigital number, since it uses as much as digits as its factorization.
11113331311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81, while the sum is 19.
Adding to 11113331311 its reverse (11313331111), we get a palindrome (22426662422).
The spelling of 11113331311 in words is "eleven billion, one hundred thirteen million, three hundred thirty-one thousand, three hundred eleven".
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