111134034113 has 2 divisors, whose sum is σ = 111134034114. Its totient is φ = 111134034112.

The previous prime is 111134034097. The next prime is 111134034127. The reversal of 111134034113 is 311430431111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57251089984 + 53882944129 = 239272^2 + 232127^2 .

It is an emirp because it is prime and its reverse (311430431111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111134034113 - 2⁴ = 111134034097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (111134039113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55567017056 + 55567017057.

It is an arithmetic number, because the mean of its divisors is an integer number (55567017057).

Almost surely, 2^111134034113 is an apocalyptic number.

It is an amenable number.

111134034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111134034113 is an equidigital number, since it uses as much as digits as its factorization.

111134034113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 111134034113 its reverse (311430431111), we get a palindrome (422564465224).

The spelling of 111134034113 in words is "one hundred eleven billion, one hundred thirty-four million, thirty-four thousand, one hundred thirteen".