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11113421012051 is a prime number
BaseRepresentation
bin1010000110111000101110…
…0000101111110001010011
31110100102200102022001222112
42201232023200233301103
52424040241234341201
635345233553255535
72224626634654001
oct241561340576123
943312612261875
1011113421012051
1135a51a2487006
1212b5a322645ab
13627cb65c2a37
142a5c6cc35a71
15144143caa0bb
hexa1b8b82fc53

11113421012051 has 2 divisors, whose sum is σ = 11113421012052. Its totient is φ = 11113421012050.

The previous prime is 11113421011981. The next prime is 11113421012117. The reversal of 11113421012051 is 15021012431111.

11113421012051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15021012431111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11113421012051 - 210 = 11113421011027 is a prime.

It is a super-4 number, since 4×111134210120514 (a number of 53 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (11113421014051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556710506025 + 5556710506026.

It is an arithmetic number, because the mean of its divisors is an integer number (5556710506026).

Almost surely, 211113421012051 is an apocalyptic number.

11113421012051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113421012051 is an equidigital number, since it uses as much as digits as its factorization.

11113421012051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 11113421012051 its reverse (15021012431111), we get a palindrome (26134433443162).

The spelling of 11113421012051 in words is "eleven trillion, one hundred thirteen billion, four hundred twenty-one million, twelve thousand, fifty-one".