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11114064553 is a prime number
BaseRepresentation
bin10100101100111001…
…10010101010101001
31001200120001222101111
422112130302222221
5140230200031203
65034500550321
7542262663364
oct122634625251
931616058344
1011114064553
114793666219
1221a20b23a1
131081753a77
147760c30db
15450ac126d
hex296732aa9

11114064553 has 2 divisors, whose sum is σ = 11114064554. Its totient is φ = 11114064552.

The previous prime is 11114064547. The next prime is 11114064581. The reversal of 11114064553 is 35546041111.

11114064553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10775062809 + 339001744 = 103803^2 + 18412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11114064553 is a prime.

It is not a weakly prime, because it can be changed into another prime (11114064503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557032276 + 5557032277.

It is an arithmetic number, because the mean of its divisors is an integer number (5557032277).

Almost surely, 211114064553 is an apocalyptic number.

It is an amenable number.

11114064553 is a deficient number, since it is larger than the sum of its proper divisors (1).

11114064553 is an equidigital number, since it uses as much as digits as its factorization.

11114064553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 31.

The spelling of 11114064553 in words is "eleven billion, one hundred fourteen million, sixty-four thousand, five hundred fifty-three".