11115506244341 has 4 divisors (see below), whose sum is σ = 11700532888800. Its totient is φ = 10530479599884.

The previous prime is 11115506244287. The next prime is 11115506244461. The reversal of 11115506244341 is 14344260551111.

11115506244341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11115506244341 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11115506244295 and 11115506244304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11115509244341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292513322201 + ... + 292513322238.

It is an arithmetic number, because the mean of its divisors is an integer number (2925133222200).

Almost surely, 2^{11115506244341} is an apocalyptic number.

It is an amenable number.

11115506244341 is a deficient number, since it is larger than the sum of its proper divisors (585026644459).

11115506244341 is an equidigital number, since it uses as much as digits as its factorization.

11115506244341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 585026644458.

The product of its (nonzero) digits is 57600, while the sum is 38.

Adding to 11115506244341 its reverse (14344260551111), we get a palindrome (25459766795452).

The spelling of 11115506244341 in words is "eleven trillion, one hundred fifteen billion, five hundred six million, two hundred forty-four thousand, three hundred forty-one".