Base | Representation |
---|---|
bin | 10000001011101000011… |
… | …011111110011010111011 |
3 | 10221022021021110101221121 |
4 | 100023220123332122323 |
5 | 121204334302210133 |
6 | 2210502445050111 |
7 | 143224266221053 |
oct | 20135033763273 |
9 | 3838237411847 |
10 | 1112001210043 |
11 | 3996627697a9 |
12 | 15b61ab56937 |
13 | 80b272747a9 |
14 | 3bb6d31c563 |
15 | 1ddd43b002d |
hex | 102e86fe6bb |
1112001210043 has 2 divisors, whose sum is σ = 1112001210044. Its totient is φ = 1112001210042.
The previous prime is 1112001210037. The next prime is 1112001210121. The reversal of 1112001210043 is 3400121002111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1112001210043 - 225 = 1111967655611 is a prime.
It is a super-2 number, since 2×11120012100432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1112001209999 and 1112001210026.
It is not a weakly prime, because it can be changed into another prime (1112001216043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556000605021 + 556000605022.
It is an arithmetic number, because the mean of its divisors is an integer number (556000605022).
Almost surely, 21112001210043 is an apocalyptic number.
1112001210043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112001210043 is an equidigital number, since it uses as much as digits as its factorization.
1112001210043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1112001210043 its reverse (3400121002111), we get a palindrome (4512122212154).
The spelling of 1112001210043 in words is "one trillion, one hundred twelve billion, one million, two hundred ten thousand, forty-three".
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