1112011009937 has 2 divisors, whose sum is σ = 1112011009938. Its totient is φ = 1112011009936.

The previous prime is 1112011009919. The next prime is 1112011010017. The reversal of 1112011009937 is 7399001102111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 713617768081 + 398393241856 = 844759^2 + 631184^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112011009937 is a prime.

It is a super-3 number, since 3×1112011009937³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1112011009897 and 1112011009906.

It is not a weakly prime, because it can be changed into another prime (1112011000937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556005504968 + 556005504969.

It is an arithmetic number, because the mean of its divisors is an integer number (556005504969).

Almost surely, 2^{1112011009937} is an apocalyptic number.

It is an amenable number.

1112011009937 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112011009937 is an equidigital number, since it uses as much as digits as its factorization.

1112011009937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 35.

The spelling of 1112011009937 in words is "one trillion, one hundred twelve billion, eleven million, nine thousand, nine hundred thirty-seven".