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111201202112113 is a prime number
BaseRepresentation
bin11001010010001100001100…
…001001101000011001110001
3112120201201201222020111220101
4121102030030021220121301
5104033410030220041423
61032301043233512401
732265010311145621
oct3122141411503161
9476651658214811
10111201202112113
113248318a645973
121057b655712701
134a082c793cab9
141d66249d88881
15ccc8e9c047ad
hex65230c268671

111201202112113 has 2 divisors, whose sum is σ = 111201202112114. Its totient is φ = 111201202112112.

The previous prime is 111201202112059. The next prime is 111201202112129. The reversal of 111201202112113 is 311211202102111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97792657226289 + 13408544885824 = 9889017^2 + 3661768^2 .

It is a cyclic number.

It is not a de Polignac number, because 111201202112113 - 225 = 111201168557681 is a prime.

It is not a weakly prime, because it can be changed into another prime (111201202112183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600601056056 + 55600601056057.

It is an arithmetic number, because the mean of its divisors is an integer number (55600601056057).

Almost surely, 2111201202112113 is an apocalyptic number.

It is an amenable number.

111201202112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111201202112113 is an equidigital number, since it uses as much as digits as its factorization.

111201202112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 111201202112113 its reverse (311211202102111), we get a palindrome (422412404214224).

The spelling of 111201202112113 in words is "one hundred eleven trillion, two hundred one billion, two hundred two million, one hundred twelve thousand, one hundred thirteen".