11120130013 has 4 divisors (see below), whose sum is σ = 11149943068. Its totient is φ = 11090316960.

The previous prime is 11120129987. The next prime is 11120130023. The reversal of 11120130013 is 31003102111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2856047364 + 8264082649 = 53442^2 + 90907^2 .

It is a cyclic number.

It is not a de Polignac number, because 11120130013 - 2¹⁷ = 11119998941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11120129975 and 11120130002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11120130023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14905968 + ... + 14906713.

It is an arithmetic number, because the mean of its divisors is an integer number (2787485767).

Almost surely, 2^11120130013 is an apocalyptic number.

It is an amenable number.

11120130013 is a deficient number, since it is larger than the sum of its proper divisors (29813055).

11120130013 is an equidigital number, since it uses as much as digits as its factorization.

11120130013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29813054.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11120130013 its reverse (31003102111), we get a palindrome (42123232124).

The spelling of 11120130013 in words is "eleven billion, one hundred twenty million, one hundred thirty thousand, thirteen".