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11119998941 is a prime number
BaseRepresentation
bin10100101101100110…
…11011011111011101
31001200222020110211122
422112303123133131
5140233204431231
65035232100325
7542364300662
oct122663333735
931628213748
1011119998941
114796a49877
1221a40946a5
131082a50c3c
14776bc9a69
1545139477b
hex296cdb7dd

11119998941 has 2 divisors, whose sum is σ = 11119998942. Its totient is φ = 11119998940.

The previous prime is 11119998917. The next prime is 11119998943. The reversal of 11119998941 is 14989991111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5823216100 + 5296782841 = 76310^2 + 72779^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11119998941 is a prime.

It is a super-2 number, since 2×111199989412 (a number of 21 digits) contains 22 as substring.

Together with 11119998943, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11119998943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5559999470 + 5559999471.

It is an arithmetic number, because the mean of its divisors is an integer number (5559999471).

Almost surely, 211119998941 is an apocalyptic number.

It is an amenable number.

11119998941 is a deficient number, since it is larger than the sum of its proper divisors (1).

11119998941 is an equidigital number, since it uses as much as digits as its factorization.

11119998941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 209952, while the sum is 53.

The spelling of 11119998941 in words is "eleven billion, one hundred nineteen million, nine hundred ninety-eight thousand, nine hundred forty-one".