Search a number
-
+
11120130122 = 25560065061
BaseRepresentation
bin10100101101100111…
…11011100001001010
31001200222111010210012
422112303323201022
5140233223130442
65035234551522
7542365355303
oct122663734112
931628433705
1011120130122
114797029392
1221a41385a2
131082a9886a
14776c217aa
154513bd582
hex296cfb84a

11120130122 has 4 divisors (see below), whose sum is σ = 16680195186. Its totient is φ = 5560065060.

The previous prime is 11120130067. The next prime is 11120130143. The reversal of 11120130122 is 22103102111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9541577761 + 1578552361 = 97681^2 + 39731^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11120130097 and 11120130106.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2780032529 + ... + 2780032532.

Almost surely, 211120130122 is an apocalyptic number.

11120130122 is a deficient number, since it is larger than the sum of its proper divisors (5560065064).

11120130122 is an equidigital number, since it uses as much as digits as its factorization.

11120130122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5560065063.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11120130122 its reverse (22103102111), we get a palindrome (33223232233).

The spelling of 11120130122 in words is "eleven billion, one hundred twenty million, one hundred thirty thousand, one hundred twenty-two".

Divisors: 1 2 5560065061 11120130122