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1112013130222 = 2556006565111
BaseRepresentation
bin10000001011101001001…
…001011100100111101110
310221022022002220000100201
4100023221021130213232
5121204400330131342
62210503552344114
7143224502435551
oct20135111344756
93838262800321
101112013130222
11399669470595
1215b622b4503a
1380b29889357
143bb70b42698
151ddd5466db7
hex102e925c9ee

1112013130222 has 4 divisors (see below), whose sum is σ = 1668019695336. Its totient is φ = 556006565110.

The previous prime is 1112013130183. The next prime is 1112013130223. The reversal of 1112013130222 is 2220313102111.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11120131302222 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1112013130222.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112013130223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278003282554 + ... + 278003282557.

It is an arithmetic number, because the mean of its divisors is an integer number (417004923834).

Almost surely, 21112013130222 is an apocalyptic number.

1112013130222 is a deficient number, since it is larger than the sum of its proper divisors (556006565114).

1112013130222 is an equidigital number, since it uses as much as digits as its factorization.

1112013130222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 556006565113.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1112013130222 its reverse (2220313102111), we get a palindrome (3332326232333).

It can be divided in two parts, 111201 and 3130222, that added together give a palindrome (3241423).

The spelling of 1112013130222 in words is "one trillion, one hundred twelve billion, thirteen million, one hundred thirty thousand, two hundred twenty-two".

Divisors: 1 2 556006565111 1112013130222