111201401 has 2 divisors, whose sum is σ = 111201402. Its totient is φ = 111201400.

The previous prime is 111201361. The next prime is 111201439. The reversal of 111201401 is 104102111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86955625 + 24245776 = 9325^2 + 4924^2 .

It is an emirp because it is prime and its reverse (104102111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111201401 is a prime.

It is not a weakly prime, because it can be changed into another prime (111201451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600700 + 55600701.

It is an arithmetic number, because the mean of its divisors is an integer number (55600701).

Almost surely, 2^111201401 is an apocalyptic number.

It is an amenable number.

111201401 is a deficient number, since it is larger than the sum of its proper divisors (1).

111201401 is an equidigital number, since it uses as much as digits as its factorization.

111201401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

The square root of 111201401 is about 10545.2074896609. The cubic root of 111201401 is about 480.8800420657.

Adding to 111201401 its reverse (104102111), we get a palindrome (215303512).

It can be divided in two parts, 11120 and 1401, that added together give a palindrome (12521).

The spelling of 111201401 in words is "one hundred eleven million, two hundred one thousand, four hundred one".