Base | Representation |
---|---|
bin | 110011110010000100… |
… | …1101111110001011001 |
3 | 101122000212001222200022 |
4 | 1213210021233301121 |
5 | 3310220144130432 |
6 | 123030243320225 |
7 | 11014454626223 |
oct | 1474411576131 |
9 | 348025058608 |
10 | 111201942617 |
11 | 43184663417 |
12 | 19675380075 |
13 | a64252165c |
14 | 554ca9b413 |
15 | 2d5c8b8b12 |
hex | 19e426fc59 |
111201942617 has 2 divisors, whose sum is σ = 111201942618. Its totient is φ = 111201942616.
The previous prime is 111201942611. The next prime is 111201942647. The reversal of 111201942617 is 716249102111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100749742921 + 10452199696 = 317411^2 + 102236^2 .
It is an emirp because it is prime and its reverse (716249102111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111201942617 - 214 = 111201926233 is a prime.
It is not a weakly prime, because it can be changed into another prime (111201942611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600971308 + 55600971309.
It is an arithmetic number, because the mean of its divisors is an integer number (55600971309).
Almost surely, 2111201942617 is an apocalyptic number.
It is an amenable number.
111201942617 is a deficient number, since it is larger than the sum of its proper divisors (1).
111201942617 is an equidigital number, since it uses as much as digits as its factorization.
111201942617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 35.
The spelling of 111201942617 in words is "one hundred eleven billion, two hundred one million, nine hundred forty-two thousand, six hundred seventeen".
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