Base | Representation |
---|---|
bin | 11001010010001100111011… |
… | …101101101110001010100011 |
3 | 112120201210210120210121022021 |
4 | 121102030323231232022203 |
5 | 104033413144011231201 |
6 | 1032301254341322311 |
7 | 32265036141021115 |
oct | 3122147355561243 |
9 | 476653716717267 |
10 | 111202000102051 |
11 | 3248355a033591 |
12 | 1057b838a06397 |
13 | 4a083c406aab1 |
14 | 1d662c3d4d3b5 |
15 | ccc944cd0ea1 |
hex | 65233bb6e2a3 |
111202000102051 has 2 divisors, whose sum is σ = 111202000102052. Its totient is φ = 111202000102050.
The previous prime is 111202000101989. The next prime is 111202000102099. The reversal of 111202000102051 is 150201000202111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111202000102051 - 29 = 111202000101539 is a prime.
It is a super-3 number, since 3×1112020001020513 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (111202000102351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55601000051025 + 55601000051026.
It is an arithmetic number, because the mean of its divisors is an integer number (55601000051026).
Almost surely, 2111202000102051 is an apocalyptic number.
111202000102051 is a deficient number, since it is larger than the sum of its proper divisors (1).
111202000102051 is an equidigital number, since it uses as much as digits as its factorization.
111202000102051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 111202000102051 its reverse (150201000202111), we get a palindrome (261403000304162).
The spelling of 111202000102051 in words is "one hundred eleven trillion, two hundred two billion, one hundred two thousand, fifty-one".
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