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11120222012103 = 326771825081571
BaseRepresentation
bin1010000111010010000011…
…1000100000001011000111
31110101002020101120200011100
42201310200320200023013
52424143203313341403
635352320502311143
72225260316342331
oct241644070401307
943332211520140
1011120222012103
1135a8072471006
1212b720ba284b3
1362882b601919
142a6316190451
151443e0db62a3
hexa1d20e202c7

11120222012103 has 12 divisors (see below), whose sum is σ = 16086268975608. Its totient is φ = 7402530847920.

The previous prime is 11120222012093. The next prime is 11120222012177. The reversal of 11120222012103 is 30121022202111.

It is not a de Polignac number, because 11120222012103 - 25 = 11120222012071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11120222012303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 912534693 + ... + 912546878.

It is an arithmetic number, because the mean of its divisors is an integer number (1340522414634).

Almost surely, 211120222012103 is an apocalyptic number.

11120222012103 is a deficient number, since it is larger than the sum of its proper divisors (4966046963505).

11120222012103 is a wasteful number, since it uses less digits than its factorization.

11120222012103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1825082254 (or 1825082251 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 11120222012103 its reverse (30121022202111), we get a palindrome (41241244214214).

The spelling of 11120222012103 in words is "eleven trillion, one hundred twenty billion, two hundred twenty-two million, twelve thousand, one hundred three".

Divisors: 1 3 9 677 2031 6093 1825081571 5475244713 16425734139 1235580223567 3706740670701 11120222012103