Base | Representation |
---|---|
bin | 11001010010001111000111… |
… | …011011011010011101101011 |
3 | 112120202000211221110200211201 |
4 | 121102033013123122131223 |
5 | 104033432444043104003 |
6 | 1032302323113505031 |
7 | 32265151212544231 |
oct | 3122170733323553 |
9 | 476660757420751 |
10 | 111204344113003 |
11 | 32484552184719 |
12 | 10580191a12177 |
13 | 4a086a888231b |
14 | 1d66467396951 |
15 | ccca30997b1d |
hex | 6523c76da76b |
111204344113003 has 2 divisors, whose sum is σ = 111204344113004. Its totient is φ = 111204344113002.
The previous prime is 111204344112971. The next prime is 111204344113013. The reversal of 111204344113003 is 300311443402111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111204344113003 - 25 = 111204344112971 is a prime.
It is a super-2 number, since 2×1112043441130032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111204344113013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55602172056501 + 55602172056502.
It is an arithmetic number, because the mean of its divisors is an integer number (55602172056502).
Almost surely, 2111204344113003 is an apocalyptic number.
111204344113003 is a deficient number, since it is larger than the sum of its proper divisors (1).
111204344113003 is an equidigital number, since it uses as much as digits as its factorization.
111204344113003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 111204344113003 its reverse (300311443402111), we get a palindrome (411515787515114).
The spelling of 111204344113003 in words is "one hundred eleven trillion, two hundred four billion, three hundred forty-four million, one hundred thirteen thousand, three".
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