11120634024343 has 4 divisors (see below), whose sum is σ = 11705930551960. Its totient is φ = 10535337496728.

The previous prime is 11120634024329. The next prime is 11120634024347. The reversal of 11120634024343 is 34342043602111.

11120634024343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11120634024343 is a prime.

It is a super-2 number, since 2×11120634024343² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11120634024299 and 11120634024308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11120634024347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292648263780 + ... + 292648263817.

It is an arithmetic number, because the mean of its divisors is an integer number (2926482637990).

Almost surely, 2^{11120634024343} is an apocalyptic number.

11120634024343 is a deficient number, since it is larger than the sum of its proper divisors (585296527617).

11120634024343 is an equidigital number, since it uses as much as digits as its factorization.

11120634024343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 585296527616.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 11120634024343 its reverse (34342043602111), we get a palindrome (45462677626454).

The spelling of 11120634024343 in words is "eleven trillion, one hundred twenty billion, six hundred thirty-four million, twenty-four thousand, three hundred forty-three".