Base | Representation |
---|---|
bin | 1010000111010101010101… |
… | …0010010110001001010011 |
3 | 1110101011111122221010222020 |
4 | 2201311111102112021103 |
5 | 2424202003401431003 |
6 | 35352544030342523 |
7 | 2225321153336232 |
oct | 241652522261123 |
9 | 43334448833866 |
10 | 11121101202003 |
11 | 35a848377a431 |
12 | 12b741635aa43 |
13 | 62893b7c0230 |
14 | 2a639ac50b19 |
15 | 144443181d53 |
hex | a1d55496253 |
11121101202003 has 16 divisors (see below), whose sum is σ = 16270058075040. Its totient is φ = 6714627139584.
The previous prime is 11121101201993. The next prime is 11121101202007. The reversal of 11121101202003 is 30020210112111.
It is not a de Polignac number, because 11121101202003 - 224 = 11121084424787 is a prime.
It is a super-2 number, since 2×111211012020032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11121101202007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2690153038 + ... + 2690157171.
It is an arithmetic number, because the mean of its divisors is an integer number (1016878629690).
Almost surely, 211121101202003 is an apocalyptic number.
11121101202003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11121101202003 is a deficient number, since it is larger than the sum of its proper divisors (5148956873037).
11121101202003 is a wasteful number, since it uses less digits than its factorization.
11121101202003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5380310278.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11121101202003 its reverse (30020210112111), we get a palindrome (41141311314114).
The spelling of 11121101202003 in words is "eleven trillion, one hundred twenty-one billion, one hundred one million, two hundred two thousand, three".
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