Base | Representation |
---|---|
bin | 1010000111010101011001… |
… | …1010000011100010000011 |
3 | 1110101011112222022012011012 |
4 | 2201311112122003202003 |
5 | 2424202023210001011 |
6 | 35352545541311135 |
7 | 2225321502201251 |
oct | 241652632034203 |
9 | 43334488265135 |
10 | 11121120000131 |
11 | 35a8493349779 |
12 | 12b74207054ab |
13 | 62894267259b |
14 | 2a639d5455d1 |
15 | 144444b46a8b |
hex | a1d56683883 |
11121120000131 has 2 divisors, whose sum is σ = 11121120000132. Its totient is φ = 11121120000130.
The previous prime is 11121120000077. The next prime is 11121120000163. The reversal of 11121120000131 is 13100002112111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121120000131 - 214 = 11121119983747 is a prime.
It is a super-2 number, since 2×111211200001312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11121120500131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560560000065 + 5560560000066.
It is an arithmetic number, because the mean of its divisors is an integer number (5560560000066).
Almost surely, 211121120000131 is an apocalyptic number.
11121120000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121120000131 is an equidigital number, since it uses as much as digits as its factorization.
11121120000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 11121120000131 its reverse (13100002112111), we get a palindrome (24221122112242).
The spelling of 11121120000131 in words is "eleven trillion, one hundred twenty-one billion, one hundred twenty million, one hundred thirty-one", and thus it is an aban number.
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