Search a number
-
+
11121122021153 is a prime number
BaseRepresentation
bin1010000111010101011010…
…0001110000111100100001
31110101011120010002212110212
42201311112201300330201
52424202024214134103
635352550052503505
72225321525316404
oct241652641607441
943334503085425
1011121122021153
1135a84944aa141
1212b742131ab95
13628942bcc461
142a639d90dd3b
15144444de57d8
hexa1d56870f21

11121122021153 has 2 divisors, whose sum is σ = 11121122021154. Its totient is φ = 11121122021152.

The previous prime is 11121122021101. The next prime is 11121122021171. The reversal of 11121122021153 is 35112022112111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9624345949969 + 1496776071184 = 3102313^2 + 1223428^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11121122021153 is a prime.

It is not a weakly prime, because it can be changed into another prime (11121122021183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560561010576 + 5560561010577.

It is an arithmetic number, because the mean of its divisors is an integer number (5560561010577).

Almost surely, 211121122021153 is an apocalyptic number.

It is an amenable number.

11121122021153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11121122021153 is an equidigital number, since it uses as much as digits as its factorization.

11121122021153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 11121122021153 its reverse (35112022112111), we get a palindrome (46233144133264).

The spelling of 11121122021153 in words is "eleven trillion, one hundred twenty-one billion, one hundred twenty-two million, twenty-one thousand, one hundred fifty-three".