Base | Representation |
---|---|
bin | 10000001011101111100… |
… | …001100000010010101011 |
3 | 10221022120120011122022202 |
4 | 100023233201200102223 |
5 | 121210110221200021 |
6 | 2210522333210415 |
7 | 143230241610044 |
oct | 20135741402253 |
9 | 3838516148282 |
10 | 1112120100011 |
11 | 399713892578 |
12 | 15b652930a0b |
13 | 80b45aa039b |
14 | 3bb810298cb |
15 | 1dddea46a0b |
hex | 102ef8604ab |
1112120100011 has 2 divisors, whose sum is σ = 1112120100012. Its totient is φ = 1112120100010.
The previous prime is 1112120099947. The next prime is 1112120100019. The reversal of 1112120100011 is 1100010212111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112120100011 - 26 = 1112120099947 is a prime.
It is a super-3 number, since 3×11121201000113 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1112120099965 and 1112120100001.
It is not a weakly prime, because it can be changed into another prime (1112120100019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556060050005 + 556060050006.
It is an arithmetic number, because the mean of its divisors is an integer number (556060050006).
Almost surely, 21112120100011 is an apocalyptic number.
1112120100011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112120100011 is an equidigital number, since it uses as much as digits as its factorization.
1112120100011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1112120100011 its reverse (1100010212111), we get a palindrome (2212130312122).
The spelling of 1112120100011 in words is "one trillion, one hundred twelve billion, one hundred twenty million, one hundred thousand, eleven".
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