Base | Representation |
---|---|
bin | 1010000111010101101110… |
… | …0000011010001110010111 |
3 | 1110101011202221021200021210 |
4 | 2201311123200122032113 |
5 | 2424202212110131043 |
6 | 35353002235112503 |
7 | 2225323561316550 |
oct | 241653340321627 |
9 | 43334687250253 |
10 | 11121205552023 |
11 | 35a8527672116 |
12 | 12b74452a2733 |
13 | 6289572c79c8 |
14 | 2a63aaa55327 |
15 | 14444c3e5633 |
hex | a1d5b81a397 |
11121205552023 has 16 divisors (see below), whose sum is σ = 17359930619136. Its totient is φ = 6199975220160.
The previous prime is 11121205551997. The next prime is 11121205552033. The reversal of 11121205552023 is 32025550212111.
11121205552023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11121205552023 - 25 = 11121205551991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11121205552033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6458306661 + ... + 6458308382.
It is an arithmetic number, because the mean of its divisors is an integer number (1084995663696).
Almost surely, 211121205552023 is an apocalyptic number.
11121205552023 is a deficient number, since it is larger than the sum of its proper divisors (6238725067113).
11121205552023 is a wasteful number, since it uses less digits than its factorization.
11121205552023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12916615094.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 11121205552023 its reverse (32025550212111), we get a palindrome (43146755764134).
The spelling of 11121205552023 in words is "eleven trillion, one hundred twenty-one billion, two hundred five million, five hundred fifty-two thousand, twenty-three".
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