Base | Representation |
---|---|
bin | 10000001011101111100… |
… | …101101100110110010001 |
3 | 10221022120122020112020201 |
4 | 100023233211230312101 |
5 | 121210111011400032 |
6 | 2210522412535201 |
7 | 143230254141052 |
oct | 20135745546621 |
9 | 3838518215221 |
10 | 1112121200017 |
11 | 399714473a73 |
12 | 15b653181501 |
13 | 80b46096c89 |
14 | 3bb81234729 |
15 | 1dddebb28e7 |
hex | 102ef96cd91 |
1112121200017 has 2 divisors, whose sum is σ = 1112121200018. Its totient is φ = 1112121200016.
The previous prime is 1112121199957. The next prime is 1112121200053. The reversal of 1112121200017 is 7100021212111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 959712163201 + 152409036816 = 979649^2 + 390396^2 .
It is a cyclic number.
It is not a de Polignac number, because 1112121200017 - 223 = 1112112811409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1112121199967 and 1112121200003.
It is not a weakly prime, because it can be changed into another prime (1112121200087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556060600008 + 556060600009.
It is an arithmetic number, because the mean of its divisors is an integer number (556060600009).
Almost surely, 21112121200017 is an apocalyptic number.
It is an amenable number.
1112121200017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112121200017 is an equidigital number, since it uses as much as digits as its factorization.
1112121200017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 1112121200017 its reverse (7100021212111), we get a palindrome (8212142412128).
The spelling of 1112121200017 in words is "one trillion, one hundred twelve billion, one hundred twenty-one million, two hundred thousand, seventeen".
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