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1112130130130 = 25111213013013
BaseRepresentation
bin10000001011110000000…
…111110001000011010010
310221022121021001020001122
4100023300013301003102
5121210120303131010
62210523332202242
7143230423063265
oct20136007610322
93838537036048
101112130130130
11399719513328
1215b656169382
1380b47ba2876
143bb824bacdc
151dde0878855
hex102f01f10d2

1112130130130 has 8 divisors (see below), whose sum is σ = 2001834234252. Its totient is φ = 444852052048.

The previous prime is 1112130130121. The next prime is 1112130130247. The reversal of 1112130130130 is 310310312111.

It can be written as a sum of positive squares in 2 ways, for example, as 1084103687209 + 28026442921 = 1041203^2 + 167411^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1112130130099 and 1112130130108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55606506497 + ... + 55606506516.

Almost surely, 21112130130130 is an apocalyptic number.

1112130130130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1112130130130 is a deficient number, since it is larger than the sum of its proper divisors (889704104122).

1112130130130 is a wasteful number, since it uses less digits than its factorization.

1112130130130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111213013020.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1112130130130 its reverse (310310312111), we get a palindrome (1422440442241).

The spelling of 1112130130130 in words is "one trillion, one hundred twelve billion, one hundred thirty million, one hundred thirty thousand, one hundred thirty".

Divisors: 1 2 5 10 111213013013 222426026026 556065065065 1112130130130