Base | Representation |
---|---|
bin | 11001010010010111010010… |
… | …100001010001010001110011 |
3 | 112120202212111120002122222011 |
4 | 121102113102201101101303 |
5 | 104034103432223212321 |
6 | 1032310334014223351 |
7 | 32265611535512116 |
oct | 3122272241212163 |
9 | 476685446078864 |
10 | 111213120132211 |
11 | 32488245aa3859 |
12 | 10581a20ab4b57 |
13 | 4a09476acccb6 |
14 | 1d66a5ab4657d |
15 | cccd9617eae1 |
hex | 6525d2851473 |
111213120132211 has 2 divisors, whose sum is σ = 111213120132212. Its totient is φ = 111213120132210.
The previous prime is 111213120132151. The next prime is 111213120132251. The reversal of 111213120132211 is 112231021312111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111213120132211 is a prime.
It is not a weakly prime, because it can be changed into another prime (111213120132251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606560066105 + 55606560066106.
It is an arithmetic number, because the mean of its divisors is an integer number (55606560066106).
Almost surely, 2111213120132211 is an apocalyptic number.
111213120132211 is a deficient number, since it is larger than the sum of its proper divisors (1).
111213120132211 is an equidigital number, since it uses as much as digits as its factorization.
111213120132211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 111213120132211 its reverse (112231021312111), we get a palindrome (223444141444322).
The spelling of 111213120132211 in words is "one hundred eleven trillion, two hundred thirteen billion, one hundred twenty million, one hundred thirty-two thousand, two hundred eleven".
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