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11121315113 is a prime number
BaseRepresentation
bin10100101101110000…
…11100110100101001
31001201001201100021202
422112320130310221
5140234024040423
65035320213545
7542411422136
oct122670346451
931631640252
1011121315113
114797768717
1221a460a2b5
1310830c203c
1477704d58d
15451554728
hex296e1cd29

11121315113 has 2 divisors, whose sum is σ = 11121315114. Its totient is φ = 11121315112.

The previous prime is 11121315109. The next prime is 11121315211. The reversal of 11121315113 is 31151312111.

11121315113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9200070889 + 1921244224 = 95917^2 + 43832^2 .

It is a cyclic number.

It is not a de Polignac number, because 11121315113 - 22 = 11121315109 is a prime.

It is not a weakly prime, because it can be changed into another prime (11121318113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560657556 + 5560657557.

It is an arithmetic number, because the mean of its divisors is an integer number (5560657557).

Almost surely, 211121315113 is an apocalyptic number.

It is an amenable number.

11121315113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11121315113 is an equidigital number, since it uses as much as digits as its factorization.

11121315113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90, while the sum is 20.

Adding to 11121315113 its reverse (31151312111), we get a palindrome (42272627224).

The spelling of 11121315113 in words is "eleven billion, one hundred twenty-one million, three hundred fifteen thousand, one hundred thirteen".