Base | Representation |
---|---|
bin | 11001010010011000001110… |
… | …010011101110010001110011 |
3 | 112120202222002110120111102021 |
4 | 121102120032103232101303 |
5 | 104034113011020321224 |
6 | 1032311021325532311 |
7 | 32265645435536464 |
oct | 3122301623562163 |
9 | 476688073514367 |
10 | 111214123213939 |
11 | 32488710231a19 |
12 | 10582060a14097 |
13 | 4a095a6878a95 |
14 | 1d66b14056d6b |
15 | ccce0426e1e4 |
hex | 65260e4ee473 |
111214123213939 has 2 divisors, whose sum is σ = 111214123213940. Its totient is φ = 111214123213938.
The previous prime is 111214123213877. The next prime is 111214123213957. The reversal of 111214123213939 is 939312321412111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111214123213939 - 213 = 111214123205747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111214123213895 and 111214123213904.
It is not a weakly prime, because it can be changed into another prime (111214123214939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55607061606969 + 55607061606970.
It is an arithmetic number, because the mean of its divisors is an integer number (55607061606970).
Almost surely, 2111214123213939 is an apocalyptic number.
111214123213939 is a deficient number, since it is larger than the sum of its proper divisors (1).
111214123213939 is an equidigital number, since it uses as much as digits as its factorization.
111214123213939 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 69984, while the sum is 43.
The spelling of 111214123213939 in words is "one hundred eleven trillion, two hundred fourteen billion, one hundred twenty-three million, two hundred thirteen thousand, nine hundred thirty-nine".
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