Base | Representation |
---|---|
bin | 1010000111010110111010… |
… | …0011111011111010011111 |
3 | 1110101012121012211200121202 |
4 | 2201311232203323322133 |
5 | 2424203340430243201 |
6 | 35353054055150115 |
7 | 2225334522542042 |
oct | 241655643737237 |
9 | 43335535750552 |
10 | 11121525243551 |
11 | 35a8681076098 |
12 | 12b751437533b |
13 | 6289a85cb6a8 |
14 | 2a63db2b2c59 |
15 | 14446a4e3c6b |
hex | a1d6e8fbe9f |
11121525243551 has 4 divisors (see below), whose sum is σ = 11121542500704. Its totient is φ = 11121507986400.
The previous prime is 11121525243509. The next prime is 11121525243559. The reversal of 11121525243551 is 15534252512111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11121525243551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11121525243559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7622810 + ... + 8963831.
It is an arithmetic number, because the mean of its divisors is an integer number (2780385625176).
Almost surely, 211121525243551 is an apocalyptic number.
11121525243551 is a deficient number, since it is larger than the sum of its proper divisors (17257153).
11121525243551 is an equidigital number, since it uses as much as digits as its factorization.
11121525243551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17257152.
The product of its digits is 60000, while the sum is 38.
Adding to 11121525243551 its reverse (15534252512111), we get a palindrome (26655777755662).
The spelling of 11121525243551 in words is "eleven trillion, one hundred twenty-one billion, five hundred twenty-five million, two hundred forty-three thousand, five hundred fifty-one".
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