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111219054517553 is a prime number
BaseRepresentation
bin11001010010011100110100…
…001111001001110100110001
3112120210102211010200200020212
4121102130310033021310301
5104034203110424030203
61032313154524513505
732266211565120113
oct3122346417116461
9476712733620225
10111219054517553
113248a810889354
1210582bb83ab895
134a09bb1404308
141d67060d553b3
15ccd0e21561d8
hex6527343c9d31

111219054517553 has 2 divisors, whose sum is σ = 111219054517554. Its totient is φ = 111219054517552.

The previous prime is 111219054517447. The next prime is 111219054517589. The reversal of 111219054517553 is 355715450912111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102303676662784 + 8915377854769 = 10114528^2 + 2985863^2 .

It is an emirp because it is prime and its reverse (355715450912111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111219054517553 - 226 = 111218987408689 is a prime.

It is not a weakly prime, because it can be changed into another prime (111219054537553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55609527258776 + 55609527258777.

It is an arithmetic number, because the mean of its divisors is an integer number (55609527258777).

Almost surely, 2111219054517553 is an apocalyptic number.

It is an amenable number.

111219054517553 is a deficient number, since it is larger than the sum of its proper divisors (1).

111219054517553 is an equidigital number, since it uses as much as digits as its factorization.

111219054517553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 945000, while the sum is 50.

The spelling of 111219054517553 in words is "one hundred eleven trillion, two hundred nineteen billion, fifty-four million, five hundred seventeen thousand, five hundred fifty-three".