Base | Representation |
---|---|
bin | 10000001011110100111… |
… | …000111010000110101011 |
3 | 10221022210211120012002022 |
4 | 100023310320322012223 |
5 | 121210301242334011 |
6 | 2210535310455055 |
7 | 143232414021224 |
oct | 20136470720653 |
9 | 3838724505068 |
10 | 1112210121131 |
11 | 39975a68879a |
12 | 15b678b0448b |
13 | 80b5b62bb15 |
14 | 3bb8cd8024b |
15 | 1dde78c98db |
hex | 102f4e3a1ab |
1112210121131 has 4 divisors (see below), whose sum is σ = 1123676204952. Its totient is φ = 1100744037312.
The previous prime is 1112210121083. The next prime is 1112210121163. The reversal of 1112210121131 is 1311210122111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1112210121131 - 222 = 1112205926827 is a prime.
It is a super-2 number, since 2×11122101211312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1112210721131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5733041765 + ... + 5733041958.
It is an arithmetic number, because the mean of its divisors is an integer number (280919051238).
Almost surely, 21112210121131 is an apocalyptic number.
1112210121131 is a deficient number, since it is larger than the sum of its proper divisors (11466083821).
1112210121131 is an equidigital number, since it uses as much as digits as its factorization.
1112210121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11466083820.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1112210121131 its reverse (1311210122111), we get a palindrome (2423420243242).
The spelling of 1112210121131 in words is "one trillion, one hundred twelve billion, two hundred ten million, one hundred twenty-one thousand, one hundred thirty-one".
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