Base | Representation |
---|---|
bin | 10000001011110100111… |
… | …100010000101010001011 |
3 | 10221022210220012211121001 |
4 | 100023310330100222023 |
5 | 121210302003444242 |
6 | 2210535341355431 |
7 | 143232424341325 |
oct | 20136474205213 |
9 | 3838726184531 |
10 | 1112210999947 |
11 | 399760128a93 |
12 | 15b679268b77 |
13 | 80b5b878b28 |
14 | 3bb8d12c615 |
15 | 1dde79eeeb7 |
hex | 102f4f10a8b |
1112210999947 has 2 divisors, whose sum is σ = 1112210999948. Its totient is φ = 1112210999946.
The previous prime is 1112210999929. The next prime is 1112211000011. The reversal of 1112210999947 is 7499990122111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112210999947 is a prime.
It is not a weakly prime, because it can be changed into another prime (1112210999917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556105499973 + 556105499974.
It is an arithmetic number, because the mean of its divisors is an integer number (556105499974).
Almost surely, 21112210999947 is an apocalyptic number.
1112210999947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112210999947 is an equidigital number, since it uses as much as digits as its factorization.
1112210999947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 734832, while the sum is 55.
The spelling of 1112210999947 in words is "one trillion, one hundred twelve billion, two hundred ten million, nine hundred ninety-nine thousand, nine hundred forty-seven".
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