111221220133 has 4 divisors (see below), whose sum is σ = 113587629120. Its totient is φ = 108854811148.

The previous prime is 111221220119. The next prime is 111221220163. The reversal of 111221220133 is 331022122111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111221220133 - 2⁵ = 111221220101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 111221220133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111221220163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1183204423 + ... + 1183204516.

It is an arithmetic number, because the mean of its divisors is an integer number (28396907280).

Almost surely, 2^111221220133 is an apocalyptic number.

It is an amenable number.

111221220133 is a deficient number, since it is larger than the sum of its proper divisors (2366408987).

111221220133 is an equidigital number, since it uses as much as digits as its factorization.

111221220133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2366408986.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 111221220133 its reverse (331022122111), we get a palindrome (442243342244).

The spelling of 111221220133 in words is "one hundred eleven billion, two hundred twenty-one million, two hundred twenty thousand, one hundred thirty-three".