Search a number
-
+
11122141433 = 131316530911
BaseRepresentation
bin10100101101110111…
…00110100011111001
31001201010021022210012
422112323212203321
5140234232011213
65035350031305
7542421433214
oct122673464371
931633238705
1011122141433
114798182527
1221a4948535
1310833211a0
147771c677b
154516694a8
hex296ee68f9

11122141433 has 8 divisors (see below), whose sum is σ = 12069125376. Its totient is φ = 10188219600.

The previous prime is 11122141423. The next prime is 11122141447. The reversal of 11122141433 is 33414122111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11122141433 - 24 = 11122141417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11122141399 and 11122141408.

It is not an unprimeable number, because it can be changed into a prime (11122141403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3263753 + ... + 3267158.

It is an arithmetic number, because the mean of its divisors is an integer number (1508640672).

Almost surely, 211122141433 is an apocalyptic number.

11122141433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11122141433 is a deficient number, since it is larger than the sum of its proper divisors (946983943).

11122141433 is a wasteful number, since it uses less digits than its factorization.

11122141433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6531055.

The product of its digits is 576, while the sum is 23.

Adding to 11122141433 its reverse (33414122111), we get a palindrome (44536263544).

The spelling of 11122141433 in words is "eleven billion, one hundred twenty-two million, one hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 13 131 1703 6530911 84901843 855549341 11122141433