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1703 = 13131

1703 has 4 divisors (see below), whose sum is σ = 1848. Its totient is φ = 1560.

The previous prime is 1699. The next prime is 1709. The reversal of 1703 is 3071.

1703 is nontrivially palindromic in base 12.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3071 = 3783.

It is not a de Polignac number, because 1703 - 22 = 1699 is a prime.

It is a Duffinian number.

1703 is an undulating number in base 12.

It is a plaindrome in base 14 and base 15.

It is a nialpdrome in base 13.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53 + ... + 78.

It is an arithmetic number, because the mean of its divisors is an integer number (462).

1703 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1703 is a deficient number, since it is larger than the sum of its proper divisors (145).

1703 is a wasteful number, since it uses less digits than its factorization.

1703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144.

The product of its (nonzero) digits is 21, while the sum is 11.

The square root of 1703 is about 41.2674205639. The cubic root of 1703 is about 11.9418482830.

Adding to 1703 its reverse (3071), we get a palindrome (4774).

The spelling of 1703 in words is "one thousand, seven hundred three", and thus it is an iban number.

Divisors: 1 13 131 1703