Base | Representation |
---|---|
bin | 10100101101110111… |
… | …10101010111000011 |
3 | 1001201010101101221022 |
4 | 22112323311113003 |
5 | 140234240431201 |
6 | 5035351220055 |
7 | 542422105022 |
oct | 122673652703 |
9 | 31633341838 |
10 | 11122202051 |
11 | 4798214024 |
12 | 21a497762b |
13 | 108334295c |
14 | 7772008b9 |
15 | 45167c41b |
hex | 296ef55c3 |
11122202051 has 2 divisors, whose sum is σ = 11122202052. Its totient is φ = 11122202050.
The previous prime is 11122202011. The next prime is 11122202123. The reversal of 11122202051 is 15020222111.
It is a weak prime.
It is an emirp because it is prime and its reverse (15020222111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11122202051 is a prime.
It is not a weakly prime, because it can be changed into another prime (11122202011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561101025 + 5561101026.
It is an arithmetic number, because the mean of its divisors is an integer number (5561101026).
Almost surely, 211122202051 is an apocalyptic number.
11122202051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122202051 is an equidigital number, since it uses as much as digits as its factorization.
11122202051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 11122202051 its reverse (15020222111), we get a palindrome (26142424162).
The spelling of 11122202051 in words is "eleven billion, one hundred twenty-two million, two hundred two thousand, fifty-one".
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