1112261317 has 4 divisors (see below), whose sum is σ = 1112414560. Its totient is φ = 1112108076.

The previous prime is 1112261299. The next prime is 1112261321. The reversal of 1112261317 is 7131622111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112261317 is a prime.

It is a super-4 number, since 4×1112261317⁴ (a number of 37 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112261291 and 1112261300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112261327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65163 + ... + 80440.

It is an arithmetic number, because the mean of its divisors is an integer number (278103640).

Almost surely, 2^1112261317 is an apocalyptic number.

It is an amenable number.

1112261317 is a deficient number, since it is larger than the sum of its proper divisors (153243).

1112261317 is an equidigital number, since it uses as much as digits as its factorization.

1112261317 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153242.

The product of its digits is 504, while the sum is 25.

The square root of 1112261317 is about 33350.5819589404. The cubic root of 1112261317 is about 1036.1014411112.

Adding to 1112261317 its reverse (7131622111), we get a palindrome (8243883428).

The spelling of 1112261317 in words is "one billion, one hundred twelve million, two hundred sixty-one thousand, three hundred seventeen".