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11123045471998 = 25561522735999
BaseRepresentation
bin1010000111011100100100…
…1011001001011011111110
31110101100112011102022000001
42201313021023021123332
52424214444120100443
635353505003024514
72225420302346665
oct241671113113376
943340464368001
1011123045471998
1135a9291212239
1212b787950b13a
13628b8b554055
142a650315dddc
15144508bd6d4d
hexa1dc92c96fe

11123045471998 has 4 divisors (see below), whose sum is σ = 16684568208000. Its totient is φ = 5561522735998.

The previous prime is 11123045471963. The next prime is 11123045472013. The reversal of 11123045471998 is 89917454032111.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×111230454719982 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2780761367998 + ... + 2780761368001.

It is an arithmetic number, because the mean of its divisors is an integer number (4171142052000).

Almost surely, 211123045471998 is an apocalyptic number.

11123045471998 is a deficient number, since it is larger than the sum of its proper divisors (5561522736002).

11123045471998 is an equidigital number, since it uses as much as digits as its factorization.

11123045471998 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5561522736001.

The product of its (nonzero) digits is 2177280, while the sum is 55.

The spelling of 11123045471998 in words is "eleven trillion, one hundred twenty-three billion, forty-five million, four hundred seventy-one thousand, nine hundred ninety-eight".

Divisors: 1 2 5561522735999 11123045471998