Base | Representation |
---|---|
bin | 110011110010111110… |
… | …0110100111000100001 |
3 | 101122002221211122200222 |
4 | 1213211330310320201 |
5 | 3310300410010423 |
6 | 123033242052425 |
7 | 11015302223135 |
oct | 1474574647041 |
9 | 348087748628 |
10 | 111232110113 |
11 | 4319a698733 |
12 | 196834aa115 |
13 | a648854947 |
14 | 5552ab13c5 |
15 | 2d603773c8 |
hex | 19e5f34e21 |
111232110113 has 2 divisors, whose sum is σ = 111232110114. Its totient is φ = 111232110112.
The previous prime is 111232110061. The next prime is 111232110193. The reversal of 111232110113 is 311011232111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111193570849 + 38539264 = 333457^2 + 6208^2 .
It is a cyclic number.
It is not a de Polignac number, because 111232110113 - 212 = 111232106017 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 111232110091 and 111232110100.
It is not a weakly prime, because it can be changed into another prime (111232110193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55616055056 + 55616055057.
It is an arithmetic number, because the mean of its divisors is an integer number (55616055057).
Almost surely, 2111232110113 is an apocalyptic number.
It is an amenable number.
111232110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
111232110113 is an equidigital number, since it uses as much as digits as its factorization.
111232110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 111232110113 its reverse (311011232111), we get a palindrome (422243342224).
The spelling of 111232110113 in words is "one hundred eleven billion, two hundred thirty-two million, one hundred ten thousand, one hundred thirteen".
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