Base | Representation |
---|---|
bin | 1010000111100001011001… |
… | …1010011101010100101001 |
3 | 1110101110212110210202200211 |
4 | 2201320112122131110221 |
5 | 2424230122340044431 |
6 | 35354241333501121 |
7 | 2225464356103165 |
oct | 241702632352451 |
9 | 43343773722624 |
10 | 11124341331241 |
11 | 35a9896741496 |
12 | 12b7b7b4a17a1 |
13 | 629036b6c378 |
14 | 2a65c72c3ca5 |
15 | 14458285a2b1 |
hex | a1e1669d529 |
11124341331241 has 2 divisors, whose sum is σ = 11124341331242. Its totient is φ = 11124341331240.
The previous prime is 11124341331193. The next prime is 11124341331251. The reversal of 11124341331241 is 14213314342111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5982426810000 + 5141914521241 = 2445900^2 + 2267579^2 .
It is a cyclic number.
It is not a de Polignac number, because 11124341331241 - 221 = 11124339234089 is a prime.
It is not a weakly prime, because it can be changed into another prime (11124341331251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562170665620 + 5562170665621.
It is an arithmetic number, because the mean of its divisors is an integer number (5562170665621).
Almost surely, 211124341331241 is an apocalyptic number.
It is an amenable number.
11124341331241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11124341331241 is an equidigital number, since it uses as much as digits as its factorization.
11124341331241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 31.
Adding to 11124341331241 its reverse (14213314342111), we get a palindrome (25337655673352).
The spelling of 11124341331241 in words is "eleven trillion, one hundred twenty-four billion, three hundred forty-one million, three hundred thirty-one thousand, two hundred forty-one".
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