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11124341331241 is a prime number
BaseRepresentation
bin1010000111100001011001…
…1010011101010100101001
31110101110212110210202200211
42201320112122131110221
52424230122340044431
635354241333501121
72225464356103165
oct241702632352451
943343773722624
1011124341331241
1135a9896741496
1212b7b7b4a17a1
13629036b6c378
142a65c72c3ca5
1514458285a2b1
hexa1e1669d529

11124341331241 has 2 divisors, whose sum is σ = 11124341331242. Its totient is φ = 11124341331240.

The previous prime is 11124341331193. The next prime is 11124341331251. The reversal of 11124341331241 is 14213314342111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5982426810000 + 5141914521241 = 2445900^2 + 2267579^2 .

It is a cyclic number.

It is not a de Polignac number, because 11124341331241 - 221 = 11124339234089 is a prime.

It is not a weakly prime, because it can be changed into another prime (11124341331251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562170665620 + 5562170665621.

It is an arithmetic number, because the mean of its divisors is an integer number (5562170665621).

Almost surely, 211124341331241 is an apocalyptic number.

It is an amenable number.

11124341331241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11124341331241 is an equidigital number, since it uses as much as digits as its factorization.

11124341331241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 31.

Adding to 11124341331241 its reverse (14213314342111), we get a palindrome (25337655673352).

The spelling of 11124341331241 in words is "eleven trillion, one hundred twenty-four billion, three hundred forty-one million, three hundred thirty-one thousand, two hundred forty-one".