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111252241153 is a prime number
BaseRepresentation
bin110011110011100100…
…1100111101100000001
3101122011100201102022001
41213213021213230001
53310321033204103
6123035241344001
711015635306204
oct1474711475401
9348140642261
10111252241153
11431aaa98459
121968a198001
13a64ca828c1
14555563193b
152d6200201d
hex19e7267b01

111252241153 has 2 divisors, whose sum is σ = 111252241154. Its totient is φ = 111252241152.

The previous prime is 111252241141. The next prime is 111252241193. The reversal of 111252241153 is 351142252111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80075982529 + 31176258624 = 282977^2 + 176568^2 .

It is a cyclic number.

It is not a de Polignac number, because 111252241153 - 221 = 111250144001 is a prime.

It is a super-2 number, since 2×1112522411532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111252241193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55626120576 + 55626120577.

It is an arithmetic number, because the mean of its divisors is an integer number (55626120577).

Almost surely, 2111252241153 is an apocalyptic number.

It is an amenable number.

111252241153 is a deficient number, since it is larger than the sum of its proper divisors (1).

111252241153 is an equidigital number, since it uses as much as digits as its factorization.

111252241153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2400, while the sum is 28.

Adding to 111252241153 its reverse (351142252111), we get a palindrome (462394493264).

The spelling of 111252241153 in words is "one hundred eleven billion, two hundred fifty-two million, two hundred forty-one thousand, one hundred fifty-three".