Base | Representation |
---|---|
bin | 1010000111100101000111… |
… | …1100110110000100100011 |
3 | 1110101120110002100121202101 |
4 | 2201321101330312010203 |
5 | 2424234144042420001 |
6 | 35354524415031231 |
7 | 2225531205256513 |
oct | 241712174660443 |
9 | 43346402317671 |
10 | 11125340201251 |
11 | 35aa2595632a1 |
12 | 12b81b9b0b517 |
13 | 629165aa2103 |
14 | 2a667dc19843 |
15 | 1445e03b6a01 |
hex | a1e51f36123 |
11125340201251 has 2 divisors, whose sum is σ = 11125340201252. Its totient is φ = 11125340201250.
The previous prime is 11125340201219. The next prime is 11125340201273. The reversal of 11125340201251 is 15210204352111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11125340201251 - 25 = 11125340201219 is a prime.
It is not a weakly prime, because it can be changed into another prime (11125340201051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562670100625 + 5562670100626.
It is an arithmetic number, because the mean of its divisors is an integer number (5562670100626).
Almost surely, 211125340201251 is an apocalyptic number.
11125340201251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11125340201251 is an equidigital number, since it uses as much as digits as its factorization.
11125340201251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 11125340201251 its reverse (15210204352111), we get a palindrome (26335544553362).
The spelling of 11125340201251 in words is "eleven trillion, one hundred twenty-five billion, three hundred forty million, two hundred one thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •