1112534441041 has 2 divisors, whose sum is σ = 1112534441042. Its totient is φ = 1112534441040.

The previous prime is 1112534441033. The next prime is 1112534441077. The reversal of 1112534441041 is 1401444352111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1069486905600 + 43047535441 = 1034160^2 + 207479^2 .

It is an emirp because it is prime and its reverse (1401444352111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1112534441041 - 2³ = 1112534441033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112534440994 and 1112534441012.

It is not a weakly prime, because it can be changed into another prime (1112534445041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556267220520 + 556267220521.

It is an arithmetic number, because the mean of its divisors is an integer number (556267220521).

Almost surely, 2^{1112534441041} is an apocalyptic number.

It is an amenable number.

1112534441041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112534441041 is an equidigital number, since it uses as much as digits as its factorization.

1112534441041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 1112534441041 its reverse (1401444352111), we get a palindrome (2513978793152).

The spelling of 1112534441041 in words is "one trillion, one hundred twelve billion, five hundred thirty-four million, four hundred forty-one thousand, forty-one".