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11125474673 is a prime number
BaseRepresentation
bin10100101110010000…
…10100010101110001
31001201100112200010112
422113020110111301
5140241110142143
65035545311105
7542461655135
oct122710242561
931640480115
1011125474673
11479a049875
1221a5a95495
131083c1a411
147778133c5
15451ac6e18
hex297214571

11125474673 has 2 divisors, whose sum is σ = 11125474674. Its totient is φ = 11125474672.

The previous prime is 11125474663. The next prime is 11125474709. The reversal of 11125474673 is 37647452111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9122733169 + 2002741504 = 95513^2 + 44752^2 .

It is a cyclic number.

It is not a de Polignac number, because 11125474673 - 216 = 11125409137 is a prime.

It is a super-4 number, since 4×111254746734 (a number of 41 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11125474673.

It is not a weakly prime, because it can be changed into another prime (11125474603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562737336 + 5562737337.

It is an arithmetic number, because the mean of its divisors is an integer number (5562737337).

Almost surely, 211125474673 is an apocalyptic number.

It is an amenable number.

11125474673 is a deficient number, since it is larger than the sum of its proper divisors (1).

11125474673 is an equidigital number, since it uses as much as digits as its factorization.

11125474673 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 141120, while the sum is 41.

The spelling of 11125474673 in words is "eleven billion, one hundred twenty-five million, four hundred seventy-four thousand, six hundred seventy-three".