11130011220131 has 2 divisors, whose sum is σ = 11130011220132. Its totient is φ = 11130011220130.

The previous prime is 11130011220101. The next prime is 11130011220151. The reversal of 11130011220131 is 13102211003111.

It is a strong prime.

It is an emirp because it is prime and its reverse (13102211003111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11130011220131 - 2¹⁴ = 11130011203747 is a prime.

It is a super-2 number, since 2×11130011220131² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11130011220101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565005610065 + 5565005610066.

It is an arithmetic number, because the mean of its divisors is an integer number (5565005610066).

Almost surely, 2^{11130011220131} is an apocalyptic number.

11130011220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130011220131 is an equidigital number, since it uses as much as digits as its factorization.

11130011220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 11130011220131 its reverse (13102211003111), we get a palindrome (24232222223242).

The spelling of 11130011220131 in words is "eleven trillion, one hundred thirty billion, eleven million, two hundred twenty thousand, one hundred thirty-one".