Base | Representation |
---|---|
bin | 10000001100100100000… |
… | …010101101110010111011 |
3 | 10221101211222011020111211 |
4 | 100030210002231302323 |
5 | 121213411303040212 |
6 | 2211150010503551 |
7 | 143261131166563 |
oct | 20144402556273 |
9 | 3841758136454 |
10 | 1113001221307 |
11 | 39a02619aa98 |
12 | 15b859a34bb7 |
13 | 80c564b6b31 |
14 | 3bc2606dda3 |
15 | 1de420949a7 |
hex | 103240adcbb |
1113001221307 has 2 divisors, whose sum is σ = 1113001221308. Its totient is φ = 1113001221306.
The previous prime is 1113001221287. The next prime is 1113001221337. The reversal of 1113001221307 is 7031221003111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113001221307 - 215 = 1113001188539 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113001221337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556500610653 + 556500610654.
It is an arithmetic number, because the mean of its divisors is an integer number (556500610654).
Almost surely, 21113001221307 is an apocalyptic number.
1113001221307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113001221307 is an equidigital number, since it uses as much as digits as its factorization.
1113001221307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 1113001221307 its reverse (7031221003111), we get a palindrome (8144222224418).
The spelling of 1113001221307 in words is "one trillion, one hundred thirteen billion, one million, two hundred twenty-one thousand, three hundred seven".
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