Base | Representation |
---|---|
bin | 10000001100100100000… |
… | …101110011111101110011 |
3 | 10221101212000200110221221 |
4 | 100030210011303331303 |
5 | 121213412010024021 |
6 | 2211150040125511 |
7 | 143261141120221 |
oct | 20144405637563 |
9 | 3841760613857 |
10 | 1113002033011 |
11 | 39a0266a4920 |
12 | 15b85a166897 |
13 | 80c5670c42b |
14 | 3bc26201b11 |
15 | 1de421a5241 |
hex | 10324173f73 |
1113002033011 has 32 divisors (see below), whose sum is σ = 1291787078400. Its totient is φ = 948300410880.
The previous prime is 1113002032937. The next prime is 1113002033023. The reversal of 1113002033011 is 1103302003111.
It is a cyclic number.
It is not a de Polignac number, because 1113002033011 - 223 = 1112993644403 is a prime.
It is a super-2 number, since 2×11130020330112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1113002033051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 57423720 + ... + 57443098.
It is an arithmetic number, because the mean of its divisors is an integer number (40368346200).
Almost surely, 21113002033011 is an apocalyptic number.
1113002033011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1113002033011 is a deficient number, since it is larger than the sum of its proper divisors (178785045389).
1113002033011 is a wasteful number, since it uses less digits than its factorization.
1113002033011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22339.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1113002033011 its reverse (1103302003111), we get a palindrome (2216304036122).
The spelling of 1113002033011 in words is "one trillion, one hundred thirteen billion, two million, thirty-three thousand, eleven".
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