Base | Representation |
---|---|
bin | 110011110101000000… |
… | …1000010001011100011 |
3 | 101122021201012011211212 |
4 | 1213222001002023203 |
5 | 3310420340301034 |
6 | 123044120100335 |
7 | 11020061061515 |
oct | 1475201021343 |
9 | 348251164755 |
10 | 111300322019 |
11 | 43225148307 |
12 | 196a23046ab |
13 | a659a18613 |
14 | 555bb89bb5 |
15 | 2d6634d2ce |
hex | 19ea0422e3 |
111300322019 has 2 divisors, whose sum is σ = 111300322020. Its totient is φ = 111300322018.
The previous prime is 111300321941. The next prime is 111300322033. The reversal of 111300322019 is 910223003111.
It is a strong prime.
It is an emirp because it is prime and its reverse (910223003111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111300322019 is a prime.
It is a super-2 number, since 2×1113003220192 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 111300321985 and 111300322003.
It is not a weakly prime, because it can be changed into another prime (111300322219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55650161009 + 55650161010.
It is an arithmetic number, because the mean of its divisors is an integer number (55650161010).
Almost surely, 2111300322019 is an apocalyptic number.
111300322019 is a deficient number, since it is larger than the sum of its proper divisors (1).
111300322019 is an equidigital number, since it uses as much as digits as its factorization.
111300322019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 111300322019 in words is "one hundred eleven billion, three hundred million, three hundred twenty-two thousand, nineteen".
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