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111300344330 = 2571590004919
BaseRepresentation
bin110011110101000000…
…1000111101000001010
3101122021201020022110012
41213222001013220022
53310420342004310
6123044120351522
711020061213540
oct1475201075012
9348251208405
10111300344330
114322516304a
12196a23155a2
13a659a25816
14555bb93d90
152d66354c05
hex19ea047a0a

111300344330 has 16 divisors (see below), whose sum is σ = 228960708480. Its totient is φ = 38160118032.

The previous prime is 111300344291. The next prime is 111300344333. The reversal of 111300344330 is 33443003111.

111300344330 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 111300344296 and 111300344305.

It is not an unprimeable number, because it can be changed into a prime (111300344333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 795002390 + ... + 795002529.

It is an arithmetic number, because the mean of its divisors is an integer number (14310044280).

Almost surely, 2111300344330 is an apocalyptic number.

111300344330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

111300344330 is an abundant number, since it is smaller than the sum of its proper divisors (117660364150).

111300344330 is a wasteful number, since it uses less digits than its factorization.

111300344330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1590004933.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 111300344330 its reverse (33443003111), we get a palindrome (144743347441).

The spelling of 111300344330 in words is "one hundred eleven billion, three hundred million, three hundred forty-four thousand, three hundred thirty".

Divisors: 1 2 5 7 10 14 35 70 1590004919 3180009838 7950024595 11130034433 15900049190 22260068866 55650172165 111300344330