Base | Representation |
---|---|
bin | 10100101110110011… |
… | …01110101011011001 |
3 | 1001201200010120012201 |
4 | 22113121232223121 |
5 | 140243242222001 |
6 | 5040231210201 |
7 | 542545525204 |
oct | 122731565331 |
9 | 31650116181 |
10 | 11130039001 |
11 | 47a1687044 |
12 | 21a7516961 |
13 | 1084b57ac3 |
14 | 77828093b |
15 | 4521c9501 |
hex | 29766ead9 |
11130039001 has 3 divisors (see below), whose sum is σ = 11130144501. Its totient is φ = 11129933502.
The previous prime is 11130038989. The next prime is 11130039007. The reversal of 11130039001 is 10093003111.
It is a happy number.
The square root of 11130039001 is 105499.
It is a perfect power (a square), and thus also a powerful number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 10093003111 = 4597 ⋅2195563.
It is not a de Polignac number, because 11130039001 - 29 = 11130038489 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11130039001.
It is not an unprimeable number, because it can be changed into a prime (11130039007) by changing a digit.
It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 52750 + ... + 158248.
It is an arithmetic number, because the mean of its divisors is an integer number (3710048167).
Almost surely, 211130039001 is an apocalyptic number.
11130039001 is the 105499-th square number.
11130039001 is the 52750-th centered octagonal number.
It is an amenable number.
11130039001 is a deficient number, since it is larger than the sum of its proper divisors (105500).
11130039001 is an frugal number, since it uses more digits than its factorization.
11130039001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 210998 (or 105499 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 19.
Multiplying 11130039001 by its product of nonzero digits (81), we get a square (901533159081 = 9494912).
The spelling of 11130039001 in words is "eleven billion, one hundred thirty million, thirty-nine thousand, one".
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